^{2}+ Bx + C = 0 that can be given as follows:

x = (- B ± √D) /2 A,

Where, 'D' is called as determinant and whose value can be given as: D = B2 – 4 AC.

Let us learn how to solve a formula for the indicated variable through an example:

**Example:**Suppose we have a quadratic equation 2 x

^{2}– 8 x + 5 = 0. Solve this equation for value of 'x'?

**Solution:**Here in this equation “x” is the indicated variable for which we need to solve quadratic formula. When given equation is compared by the general equation, we see that A = 2, B = - 8 and C = 5. Formula we have to solve for 'x' can be given as follows:

x = (- B - √D) /2 a and x = (- B + √D) /2 A or

x = (- B - √ (B

^{2}– 4 A C)) /2 A and x = (- B + √(B

^{2}– 4 A C)) /2 A,

Substituting values of A, B and C in above formula we get the value of indicted variable 'x' as:

x = (8 - √ (8

^{2}– 4 * 2 * 5)) /2 * 2 and x = (8 + √(8

^{2}– 4 * 2 * 5)) /2 * 2,

x = (8 - √24) /4 and x = (8 + √24) /4

x = (4 - √6) /2 and x = (4 - √6) /2

Thus we get two values for indicated variable 'x'.