Sn = n / 2 [2 * a + (n - 1) * d],
Now there are some important points regarding sum of arithmetic progression formula. Points are given below-
1. If there are three known variables in formula then fourth one can be calculated easily.
2. If sum of first 'n' terms of an arithmetic progression is Sn then n th term of arithmetic progression can be found with the help of following formula:
Tn = Sn – Sn – 1,
Where Tn is n th term of arithmetic progression.
3. If sum of terms existing in arithmetic progression is given then selection of terms should be in following manner:
· If total number of terms are odd then,
Number of terms are 3 then terms should be assumed as a - d, a, a + d.
Number of terms are 5 then selection of terms should be a - (2 * d), a - d, a, a + d, a + (2 * d).
· If total number of terms are even then,
Number of terms are 4 then terms will be as a - (3 * d), a - d, a + d, a + (3 * d)
Number of terms are 6 then selection will be as a - (5 * d), a - (3 * d), a - d, a + d, a + (3 * d),
a + (5 * d),
